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A stone is thrown in a vertically upward direction with a velo... - Science
A stone is thrown in a vertically upward direction with a velocity of 5 \text{ m s}^{-1}. If the acceleration of the stone during its motion is 10 \text{ m s}^{-2} in the downward direction, what will be the height attained by the stone and how much time will it take to reach there?
Given:
Initial velocity (u) = 5 \text{ m/s}
Acceleration (a) = -10 \text{ m/s}^2 (negative because it acts downwards against the motion)
Final velocity (v) = 0 (at maximum height)
(i) Height attained (s):
Formula: v^2 - u^2 = 2as(0)^2 - (5)^2 = 2 \times (-10) \times s-25 = -20ss = \frac{25}{20} = 1.25 \text{ m}
(ii) Time taken (t):
Formula: v = u + at0 = 5 + (-10) \times t10t = 5t = \frac{5}{10} = 0.5 \text{ s}
Answer: The stone attains a height of 1.25 \text{ m} and takes 0.5 \text{ s} to reach there.