Get Updates
Subscribe to receive instant notifications for new study materials and important updates.
A farmer moves along the boundary of a square field of side 10... - Science
Question
A farmer moves along the boundary of a square field of side 10 m in 40 s. What will be the magnitude of displacement of the farmer at the end of 2 minutes 20 seconds from his initial position?
Answer
Given:
Side of the square field = 10\text{ m}
Time taken for one round = 40\text{ s}
Total time = 2\text{ min } 20\text{ s} = (2 \times 60) + 20 = 140\text{ s}
Number of rounds covered:
= \frac{\text{Total Time}}{\text{Time for 1 round}} = \frac{140}{40} = 3.5\text{ rounds}
After
3.5 rounds, the farmer is at the diagonally opposite corner of the field.
Displacement:= \text{Diagonal of the square}= \sqrt{10^2 + 10^2}= \sqrt{200}= 10\sqrt{2}\text{ m} (or 14.14\text{ m})