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A hammer of mass 500 g, moving at 50 m s⁻¹, strikes a nai... - Science
A hammer of mass 500 g, moving at 50 m s⁻¹, strikes a nail. The nail stops the hammer in a very short time of 0.01 s. What is the force of the nail on the hammer?
Given:
Mass of the hammer (
m) =500 \text{ g} = 0.5 \text{ kg}Initial velocity (
u) =50 \text{ m s}^{-1}Final velocity (
v) =0 \text{ m s}^{-1}(since it stops)Time (
t) =0.01 \text{ s}
Formula: F = m \times a = \frac{m(v - u)}{t}
Calculation:
F = \frac{0.5(0 - 50)}{0.01}F = \frac{0.5 \times (-50)}{0.01}F = \frac{-25}{0.01}F = -2500 \text{ N}
Answer:
The force of the nail on the hammer is -2500 \text{ N}.
(The negative sign indicates that the force acts in the direction opposite to the motion of the hammer).