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A stone is released from the top of a tower of height 19.6 m. ... - Science
Question
A stone is released from the top of a tower of height 19.6 m. Calculate its final velocity just before touching the ground.
Answer
Given:
Initial velocity (
u) =0 \text{ m/s}(since it is released)Height (
h) =19.6 \text{ m}Acceleration due to gravity (
g) =9.8 \text{ m/s}^2
Formula: v^2 - u^2 = 2gh
Calculation:
v^2 - 0^2 = 2 \times 9.8 \times 19.6v^2 = 19.6 \times 19.6v = \sqrt{(19.6)^2}v = 19.6 \text{ m/s}
Answer:
The final velocity is 19.6 \text{ m/s}.